1852 United States presidential election in Tennessee

Election in Tennessee

1852 United States presidential election in Tennessee
← 1848 November 2, 1852 1856 →
 
Nominee Winfield Scott Franklin Pierce
Party Whig Democratic
Home state New Jersey New Hampshire
Running mate William A. Graham William R. King
Electoral vote 12 0
Popular vote 58,586 56,900
Percentage 50.73% 49.27%

County Results

Scott

  50–60%
  60–70%
  70–80%
  80–90%

Pierce

  50–60%
  60–70%
  70–80%
  80–90%


President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

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The 1852 United States presidential election in Tennessee took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose twelve representatives, or electors to the Electoral College, who voted for President and Vice President.

Tennessee voted for the Whig candidate, Winfield Scott, over Democratic candidate Franklin Pierce.

Tennessee was one of the four states to vote for Scott in the 1852 election with the other three being Kentucky, Massachusetts and Vermont.

Despite Scott winning the state by a narrow margin of 1.46%, Tennessee would prove to be Scott's second strongest state in the nation after Kentucky.[1]

Results

1852 United States presidential election in Tennessee[2][3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 58,586 50.73% 12 100.00%
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 56,900 49.27% 0 0.00%
Total 115,486 100.00% 12 100.00%

References

  1. ^ "1852 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. ^ "1852 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved December 2, 2017.
  3. ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 2, 2017.