1879 Rhode Island gubernatorial election

1879 Rhode Island gubernatorial election

← 1878 April 2, 1879 1880 →
 
Nominee Charles C. Van Zandt Thomas W. Segar
Party Republican Democratic
Popular vote 9,717 5,506
Percentage 62.09% 35.18%

Governor before election

Charles C. Van Zandt
Republican

Elected Governor

Charles C. Van Zandt
Republican

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The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.

General election

Candidates

Major party candidates

  • Charles C. Van Zandt, Republican
  • Thomas W. Segar, Democratic

Other candidates

  • Samuel Hill, Independent

Results

1879 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Charles C. Van Zandt (incumbent) 9,717 62.09%
Democratic Thomas W. Segar 5,506 35.18%
Greenback Samuel Hill 318 2.03%
Majority 4,211
Turnout
Republican hold Swing

References

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved November 1, 2020.